x^2+3(x-4)=28

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Solution for x^2+3(x-4)=28 equation:


Simplifying
x2 + 3(x + -4) = 28

Reorder the terms:
x2 + 3(-4 + x) = 28
x2 + (-4 * 3 + x * 3) = 28
x2 + (-12 + 3x) = 28

Reorder the terms:
-12 + 3x + x2 = 28

Solving
-12 + 3x + x2 = 28

Solving for variable 'x'.

Reorder the terms:
-12 + -28 + 3x + x2 = 28 + -28

Combine like terms: -12 + -28 = -40
-40 + 3x + x2 = 28 + -28

Combine like terms: 28 + -28 = 0
-40 + 3x + x2 = 0

Factor a trinomial.
(-8 + -1x)(5 + -1x) = 0

Subproblem 1

Set the factor '(-8 + -1x)' equal to zero and attempt to solve: Simplifying -8 + -1x = 0 Solving -8 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1x = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1x = 0 + 8 -1x = 0 + 8 Combine like terms: 0 + 8 = 8 -1x = 8 Divide each side by '-1'. x = -8 Simplifying x = -8

Subproblem 2

Set the factor '(5 + -1x)' equal to zero and attempt to solve: Simplifying 5 + -1x = 0 Solving 5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1x = 0 + -5 -1x = 0 + -5 Combine like terms: 0 + -5 = -5 -1x = -5 Divide each side by '-1'. x = 5 Simplifying x = 5

Solution

x = {-8, 5}

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